HOME | DD
#brownskin #cartoon #cute #girl #portrait #rose #spanish
Published: 2015-07-24 23:40:23 +0000 UTC; Views: 1179; Favourites: 45; Downloads: 0
Redirect to original
Description
My spanish baby. She is pure <3Result of my personal artistic renaissance.Β
Related content
Comments: 15
feathers-Ruffled In reply to ponyfan19 [2015-08-19 18:07:12 +0000 UTC]
When I come up with another good idea. Got some other characters that need their portrait done as well. But don't worry, she isnt gone Β
π: 0 β©: 1
ponyfan19 In reply to feathers-Ruffled [2015-08-20 00:25:10 +0000 UTC]
Looking forward to it
π: 0 β©: 0
EPICamiture2099 [2015-08-04 00:41:58 +0000 UTC]
What a cute little latina, she even has her own cute little mole on her cheek
π: 0 β©: 0
PEPPERTODE [2015-07-27 10:08:13 +0000 UTC]
Lookin' even better than before!
The flower in her hair's a great addition!
What inspired your "personal artistic renaissance," if I may ask?
π: 0 β©: 1
feathers-Ruffled In reply to PEPPERTODE [2015-07-27 16:12:24 +0000 UTC]
I dunno really. I change styles so often but I guess it was the pencil brush itself. Plus I Β found some artwork from other artists and was all like " Thats what my style has to be."
π: 0 β©: 0
Connan-Bell [2015-07-25 18:51:59 +0000 UTC]
Awww, Hola, Rosita! Que pasa, eh?Β
(Hello Rosie! What's up?)Β
π: 0 β©: 1
feathers-Ruffled In reply to Connan-Bell [2015-07-25 19:32:30 +0000 UTC]
I think you mean Maria.Β
π: 0 β©: 1
Connan-Bell In reply to feathers-Ruffled [2015-07-25 21:14:02 +0000 UTC]
Aww, I thought her name was Rosa.Β
π: 0 β©: 1
feathers-Ruffled In reply to Connan-Bell [2015-07-25 21:18:07 +0000 UTC]
Thats her last name. Best to check this if you haven't already.Β
π: 0 β©: 1
Connan-Bell In reply to feathers-Ruffled [2015-07-25 22:09:29 +0000 UTC]
Oooooooooh! I get it now!Β
π: 0 β©: 0
Schnuron [2015-07-24 23:59:47 +0000 UTC]
She looks pretty, Matt. I also like the texture you've added in that picture, too.
The shades and the lighting effect look pretty nice, too.
The rosa or rose fits well for her, in my opinion.
π: 0 β©: 0
1





















